第一次发帖，先试试水，希望排版别太乱 今天给大家分享一串哈夫(2)

{

for( i = m ; i <= n-1 ; i++ )

{

min = h[i].weight ;pos = i ; flag = 0 ;

for ( j=i+1 ; j <= n ; j++ )

{

if( h[j].weight < min )

{

min = h[j].weight ;pos = j ; flag = 1 ;

}

}

if ( flag == 1 )

{

temp = h[i];h[i]=h[pos];h[pos]=temp ;

}

}

}

} else if (mstate.action == action_open || mstate.action == action_create 。 if-else if-else if 1 else 2 else 0 10 else 2 if if if 。if语句在没有else语句和else if 语句前提下，一个或者多个if语句使用，系统会一致判定if语句直到结束，如果有else if 语句，系统判定如果else if 后条件符合要求就会终止判断，直接输出结果，若不符合判定下一个else if符合后再次终止判断，以此类推。

{

for ( i = m ; i <= n-1 ; i++ )

{

min = h[i].suffix ;pos = i; flag = 0 ;

for ( j=i+1 ; j <= n ; j++ )

{

if( h[j].suffix < min )

{

min = h[j].suffix ;pos = j ; flag = 1 ;

}

}

if ( flag == 1 )

{

temp = h[i];h[i]=h[pos];h[pos]=temp ;

}

}

}

/*注意，下面的冒泡排序是跟上面选择排序做对照的，正常情况下用一种排序就可以了*/

else if ( action == 2 ) //action == 2, 用冒泡法依权值大小从小到大排序

{

for ( i = m ; i <= n-1 ; i++ )

for( j = m ; j <= n-i ; j++ )

{

if ( h[j].weight > h[j+1].weight )

{

temp = h[j] ;

h[j] = h[j+1] ;

h[j+1] = temp ;

}

}

}

else //else, 用冒泡法依下标进行顺序排序

{

for ( i = m ; i<= n-1 ; i++ )

for ( j = m ; j <= n-i ; j++ )

{

if ( h[j].suffix > h[j+1].suffix )

{

temp = h[j] ;

h[j] = h[j+1] ;

h[j+1] = temp ;

}

}

}

}

void Merge( hNode h[] )//将数组结点h[]合并成哈弗曼树

{

int i,j,k ;

for ( i = 1 ; i < N ;i++ )

{

j = 2*i-1 ; //j (j+1)分别是1(2)、3(4)、5(6)...

Sort( h ,j ,N+i-1 ,0) ;//新结点生成之前都依权值拍好序，确保开头两个最小

/*但是在这里把 "0 选择排序" 改为 "2 冒泡法" ,最后生成的编码是等长的 QAQ*/

weight of the goods alone without any immediate wrappings, e.g., the weight of the contents of a tin can without the weight of the can. also called actual net weight.。8. to reduce weight what method has tried a round mass of food, drink tea reducing weight, eat point of moxibustion of medicine reducing weight, give or have an acupuncture treatment, point what to still have all of and so on of all sorts of the thin body soup that circulates on the net, law reducing weight has tried, the effect is not very good, some methods are thin at that time, did not pass a few days to rebound again come back.。产品b，smalloversize，dimensional weight是8lb，unit weight是10lb，取其大者计算outbound shipping weight即是11lb，那么fulfillmentfee就是$0.00+$4.03+1.34+(0.39*(11-2))=$8.88。

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