ge=he∵ef⊥ab,ae=be∴fa=fb同理。
7.如图,ea⊥ab,bc⊥ab,ab=ae=2bc,d为ab的中点,有以下判断:①de=ac。
解析:过b作bf∥ae,则cd∥bf∥ae.根据平行线的性质即可求解.过b作bf∥ae,则cd∥bf∥ae,∴∠bcd+∠1=180°.又∵ab⊥ae,∴ab⊥bf,∴∠abf=90°,∴∠abc+∠bcd=90°+180°=270°.故答案为270.。
ALLENBRADLEY1768-L45RQANS21768L45
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联系地址:桂林市上海路15 号a5座三楼304 室。
纸质版响应文件递交地点:桂林市上海路15 号a5 座302 室。
地址:桂林市上海路15号a5座三楼304室。
联系地址:桂林市上海路15 号a5 座三楼304 室。
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AllenBradley150A97NCDNSFP**GENUINE**AB150A97NCD
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ALLENBRADLEY2711-T10G15SERBREVAFRN4.20PANELVIEW*NEWINABOX*
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comablet","b600016gwifi8寸铂银","2040","电询" "yoga11s","i3-40204g128g固态11寸平板电脑二合一橙色","4850","" "yoga11s","i3-40204g128g固态11寸平板电脑二合一银色","4850","" "yoga13","i5-33374g128g固态13寸平板电脑二合一橙色","6180","" "yoga13","i5-33374g128g固态13寸平板电脑二合一银色","6250","电询" "yoga211","n35204g500g11寸平板电脑二合一橙色","4080","" "yoga213","i3-40104g500g13寸平板电脑二合一灰色","5260","" "yoga213","i5-42004g500g13寸平板电脑二合一 橙色 ","6180","" "yoga213","i5-42004g500g13寸平板电脑二合一 银色 ","6180","" "flex14","i3-4010/4g/500g/2g独显/14。
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