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电脑杂谈  发布时间:2019-03-07 22:07:42  来源:网络整理

ge=he∵ef⊥ab,ae=be∴fa=fb同理。

7.如图,ea⊥ab,bc⊥ab,ab=ae=2bc,d为ab的中点,有以下判断:①de=ac。

解析:过b作bf∥ae,则cd∥bf∥ae.根据平行线的性质即可求解.过b作bf∥ae,则cd∥bf∥ae,∴∠bcd+∠1=180°.又∵ab⊥ae,∴ab⊥bf,∴∠abf=90°,∴∠abc+∠bcd=90°+180°=270°.故答案为270.。

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纸质版响应文件递交地点:桂林市上海路15 号a5 座302 室。

地址:桂林市上海路15号a5座三楼304室。

联系地址:桂林市上海路15 号a5 座三楼304 室。

ALLENBRADLEY1336F-B025-AN-ENRQAUS11336FB025ANEN

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