
ID验证码规则: 前17位数字彼此相乘,将每个乘积相加并除以11,得到余数,最后找到相对于余数的校验码. 7校验码不对,9,10,5,8,4,2,1,6,3,7,9,9,10,5,8,4,2,0,1,2,3,4,5,6, 7,8,9,10 1,0,X,9,8,7,6,5,4,3,2范例: 范例: 230602199801050622: (2×7 + 3×9 + 0×10 + 6×5 + 0×8 + 2×4 +…… + 6×4 + 2×2)÷11 =(14 + 27 + 0 + 30 + 0 + 8 +……+ 24 + 4)÷11 = 20……10 0校验码不对,1,2,3,4,5,6,7,8,9,10 1,0,X,9 ,8、7、6、5、4、3、2应用: 应用: 23060419980630192X: (2×7 + 3×9 + 0×10 + 6×5 + 0×8 + 2×4 +……+ 9×4 + 2×2)÷11 =(14 + 27 + 0 + 30 + 0 + 8 + 8 +……+ 36 + 4 )÷11 = 308……0 0,1,2,3,4,5,6,7,8,9,10 1,0,X,9,8,7,6,5,4,4,3,2 ﹎﹎﹎﹎﹎﹎﹎﹎﹎﹎﹎﹎﹎﹎﹎﹎﹎﹎﹎﹎﹎﹎﹎﹎﹎﹎﹎﹎﹎﹎﹎﹎﹎﹎﹎﹎﹎﹎﹎﹎﹎﹎﹎﹎﹎﹎﹎﹎﹎﹎﹎﹎﹎﹎﹎﹎﹎﹎﹎﹎﹎﹎﹎﹎原始的15位ID号: 230604980630192)□23060419980630492X□23060419980630142X□ >
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