c多线程面试题同步_高级java多线程面试题_多线程面试题(22)

{printf("error1");

exit(-1);

}fp2 = fopen("b.txt","w");

if(fp2 == NULL)

{printf("error2");

exit(-1);

}int i = 0;

int j = 0;while(fscanf(fp1,"%d",&a[i]) != EOF)

{

i++;

j++;

if(i >= MAX)

{

MAX = 2 * MAX;

b = (int*)realloc(a,MAX * sizeof(int));

if(b == NULL)

{

printf("error3");

exit(-1);

}

a = b;

}

}for(;--j >= 0;)

fprintf(fp2,"%d/n",a[j]);fclose(fp1);

fclose(fp2);return 0;

}第二题.

#include <stdio.h>int main(void)

{

unsigned long int i,j,k;printf("please input the number/n");

scanf("%d",&i);

if( i % 2 == 0)

j = i / 2;

else

j = i / 2 + 1;printf("The result is /n");

for(k = 0; k < j; k++)

printf("%d = %d + %d/n",i,k,i - k);

return 0;

}#include <stdio.h>

void main()

{

unsigned long int a,i=1;

scanf("%d",&a);

if(a%2==0)

{

for(i=1;i<a/2;i++)

printf("%d",a,a-i);

}

else

for(i=1;i<=a/2;i++)

printf(" %d, %d",i,a-i);

}兄弟,这样的题目若是做不出来实在是有些不应该, 给你一个递规反向输出字符串的例子,可谓是反序的经典例程.void inverse(char *p)

{

if( *p = = '/0' )

return;

inverse( p+1 );

printf( "%c", *p );

}int main(int argc, char *argv[])

{

inverse("abc/0");return 0;

}借签了楼上的“递规反向输出”

#include <stdio.h>

void test(FILE *fread, FILE *fwrite)

{

char buf[1024] = {0};

if (!fgets(buf, sizeof(buf), fread))

return;

test( fread, fwrite );

fputs(buf, fwrite);

}

int main(int argc, char *argv[])

{

FILE *fr = NULL;

FILE *fw = NULL;

fr = fopen("data", "rb");

fw = fopen("dataout", "wb");

test(fr, fw);

fclose(fr);

fclose(fw);

return 0;

}在对齐为4的情况下

struct BBB

{

long num；

char *name;

short int data;

char ha;

short ba[5];

本文来自电脑杂谈，转载请注明本文网址：
http://www.pc-fly.com/a/jisuanjixue/article-36439-22.html