c++ strchr函数_strchr函数返回_模拟实现strchr函数(14)

//inta,b,c,d;

for(int i=0;i<4;i)

{cin>>a[i];

v.push_back(a[i]);}// 将带入向量

//v.push_back(b);

//v.push_back(c);

//v.push_back(d);

vector<int>::const_iterator i; //常量迭代器

for(i=v.begin();i!=v.end();i)

cout<<*i<<",";

cout<<endl;

vector<int>::reverse_iterator r; //反向迭代器

for(r=v.rbegin();r!=v.rend();r)

cout<<*r<<".";

cout<<endl;

vector<int>::iterator j; //非常量迭代器

for(j=v.begin();j!=v.end();j)

*j=100;

for(i=v.begin();i!=v.end();i)

cout<<*i<<".";

return 0;

}

输入：1 2 3 4

输出结果：1,2,3,4,

4.3.2.1.

100.100.100.100.

#include <iostream>

#include <algorithm>

#include <vector>

using namespace std;

int main ()

{

int first[] = {5,10,15,20,25};

int second[] = {50,40,30,20,10};

vector<int> v(10);

vector<int>::iterator it;

sort (first,first5);

sort (second,second5);

it=set_union (first, first5, second, second5, v.begin());

cout << "union has " << int(it - v.begin())<< " elements.\n";

return 0;

}

输出结果：union has8 elements.

#include <iostream>

#include <algorithm>

#include <vector>

using namespace std;

int main(int argc, char** argv)

{

int A[] = {5,10,15,20,25};

int B[] = {50,40,30,20,10};

int C[10] = {0};

size_t size_A, size_B, size_C;

vector<int> v;

vector<int>::iterator it;

size_A = sizeof(A)/sizeof(A[0]);

size_B = sizeof(B)/sizeof(B[0]);

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